[cfe-dev] Error when testing clang with VC++ RTL and Boost MPL
James Dennett
james.dennett at gmail.com
Wed Nov 13 15:24:48 PST 2013
On Wed, Nov 13, 2013 at 3:03 PM, Edward Diener
<eldlistmailingz at tropicsoft.com> wrote:
> On 11/13/2013 5:08 PM, David Blaikie wrote:
>>
>>
>>
>>
>> On Wed, Nov 13, 2013 at 1:58 PM, Edward Diener
>> <eldlistmailingz at tropicsoft.com
>> <mailto:eldlistmailingz at tropicsoft.com>> wrote:
>>
>> On 11/13/2013 2:59 PM, Jordan Rose wrote:
>>
>>
>> On Nov 13, 2013, at 11:47 , Edward Diener
>> <eldlistmailingz at tropicsoft.__com
>> <mailto:eldlistmailingz at tropicsoft.com>
>> <mailto:eldlistmailingz at __tropicsoft.com
>>
>> <mailto:eldlistmailingz at tropicsoft.com>>>
>> wrote:
>>
>> On 11/13/2013 9:46 AM, Edward Diener wrote:
>>
>> I am seeing this error when testing Boost MPL with clang
>> using the VC++
>> RTL:
>>
>> "bitwise.cpp(40,25) : error: non-type template argument
>> evaluates to
>> 4294967295, which cannot be narrowed to type 'long'
>> [-Wc++11-narrowing]
>> MPL_ASSERT_RELATION( (bitor_<_0,_ffffffff>::value), ==,
>> 0xffffffff );"
>>
>> The typedefs are:
>>
>> typedef integral_c<unsigned int, 0> _0;
>> typedef integral_c<unsigned int, 0xffffffff> _ffffffff;
>>
>> The bitor_ in the Boost MPL is evaluating constants at
>> compile time,
>> doing a bitwise or ('|').
>>
>> Why does clang think that 0xffffffff is a 'long' when
>> used in the
>> comparison ? According to the C++ standard the type of
>> 0xffffffff is the
>> first of int, unsigned int, long, unsigned long, long
>> long, unsigned
>> long long in which its value can fit ( section 2.14.2 ).
>> Is this a clang
>> bug ?
>>
>>
>> Sorry, the problem is not as I had assumed above. It is
>> actually
>> because the MPL_ASSERT_RELATION macro devolves down to a
>> template
>> class where the values are of type 'long'. Is there
>> something in C++11
>> which says that implicit conversion of a value from an
>> 'unsigned int'
>> to a 'long' is illegal ? That is what clang is telling me
>> but I can
>> find no such restriction in the C++11 standard regarding this.
>>
>>
>> I think it’s more likely that on Windows ‘long’ is the same size
>> as
>> ‘int’, and so you have an overflow error. You need to fix the
>> template…which I guess means submitting a patch to Boost.
>>
>>
>> I tried a patch of the test code where I set:
>>
>> typedef integral_c<int, 0xffffffff> _ffffffff;
>>
>> but clang still complains that:
>>
>> bitwise.cpp(23,24) : error: non-type template argument evaluates to
>> 4294967295, which cannot be narrowed to type 'int' [-Wc++11-narrowing]
>> typedef integral_c<int, 0xffffffff> _ffffffff;
>>
>> This I do not understand. Why does 0xffffffff evaluate to 4294967295
>> rather than -1 ? Where in the C++ standard does it say that hex
>> literals are unsigned values by default ?
>>
>>
>> Nothing to do with hex literals, just literals in general. If they don't
>> fit in the range of an int, the literal is of unsigned int type so it
>> can fit the value.
>
>
> Is not -1 in the range of an 'int' ?
Yes.
> Is not 0xffffffff equivalent to -1 as a
> signed value ?
I'm not sure that's even a well-formed question. 0xffffffff (on a
32-bit platform) is _not_ a signed value, so it's not _anything_ "as a
signed value". In a context that requires a converted constant
expression, it's not convertible to a signed int (because its value is
not in the range of int -- its value is 2^31-1, not -1).
-- James
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