[clang-tools-extra] r221272 - [clang-tidy] Don't print a message if there's no error.
Alexander Kornienko
alexfh at google.com
Tue Nov 4 16:07:18 PST 2014
The intent of this code is to allow handling of three distinct cases:
1. a valid ClangTidyOptions instance
2. an error with a message
3. no error and no ClangTidyOptions, so the code just goes on looking for
a configuration file without displaying an error
Case 3 could be handled by introducing a separate return-by-reference
boolean flag or something like that, but here I preferred to use a valid
state of the ErrorOr class: HasError + std::error_code containing 0
(success). If this looks confusing, I can add a comment describing this
case.
On Tue, Nov 4, 2014 at 12:24 PM, David Blaikie <dblaikie at gmail.com> wrote:
>
>
> On Tue, Nov 4, 2014 at 12:23 PM, Justin Bogner <mail at justinbogner.com>
> wrote:
>
>> David Blaikie <dblaikie at gmail.com> writes:
>> > This is totally wrong. ErrorOr's implicit bool conversion is true
>> iff
>> > there is an error,
>> >
>> > Doesn't look like it:
>> >
>> > ErrorOr.h:
>> > /// \brief Return false if there is an error.
>> > LLVM_EXPLICIT operator bool() const {
>> > return !HasError;
>> > }
>>
>> Oops, I misinterpreted "An implicit conversion to bool provides a way to
>> check if there was an error." - I'll probably clarify that RSN. In any
>> case, isn't the added check here redundant then?
>>
>
> Yep, looks redundant to me.
>
>
>>
>> Maybe it would avoid confusion to use this (fairly common) pattern:
>>
>> llvm::ErrorOr<ClangTidyOptions> ParsedOptions =
>> ConfigHandler.second((*Text)->getBuffer());
>> if (std::error_code EC = ParsedOptions.getError()) {
>>
>
> Agreed, this seems fairly canonical.
>
>
>> // ...
>> }
>>
>> >
>> > so !ParsedOptions implies !ParsedOptions.getError().
>> >
>> > I think you want:
>> >
>> > llvm::ErrorOr<ClangTidyOptions> ParsedOptions =
>> > ConfigHandler.second((*Text)->getBuffer());
>> > if (ParsedOptions) {
>> > llvm::errs() << "Error parsing " << ConfigFile << ": "
>> > << ParsedOptions.getError().message() << "\n";
>> > ...
>> >
>> > This obviously changes the behaviour, but the current behaviour
>> doesn't
>> > make sense.
>> >
>> > > continue;
>> > > }
>> > >
>> > >
>> > >
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>
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