[llvm-dev] Get the class name of the function

[David Blaikie via llvm-dev]

I believe LLVM's demangler (llvm-cxxfilt?) is built on a reusable library
that probably provides you with APIs for inspecting the resulting name in
some ways like what you want - but I don't know for sure.

On Wed, Feb 26, 2020 at 10:55 PM zxhuan via llvm-dev <
llvm-dev at lists.llvm.org> wrote:

> Hey guys,
>
> I'm wondering if there is a way to write an llvm pass to get the class
> name of the functions. I am not talking about the simple self-written
> functions like foo::bar(...), but those STL container functions like
> _ZNKSt4lessINSt7__cxx1112basic_stringIcSt11char_traitsIcESaIcEEEEclERKS5_S8_,
> demangles as std::less<std::__cxx11::basic_string<char,
> std::char_traits<char>, std::allocator<char> >
> >::operator()(std::__cxx11::basic_string<char, std::char_traits<char>,
> std::allocator<char> > const&, std::__cxx11::basic_string<char,
> std::char_traits<char>, std::allocator<char> > const&) const. In this case,
> the class name should be std::less<std::__cxx11::basic_string<char,
> std::char_traits<char>, std::allocator<char> > >, and the function name
> is operator().
>
> I have tried to do this with clang tools, but the template parameters are
> not expanded and you can get pretty less information, which is not what
> I am looking for.
>
> PS. This is specifically for C++.
>
> Any help would be appreciated!
>
> Jason
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