[llvm-dev] Taking over an x86 opcode for my own instruction

Gus Smith via llvm-dev llvm-dev at lists.llvm.org
Wed Mar 28 13:47:22 PDT 2018


tl;dr, I'd like to add my own instruction, but I'm running into problems
due to my lack of x86 encoding/decoding understanding.

Hello all. Currently, I'm working on adding my own x86 instruction. I have
done this once before; the basic process I used was:

   1. Find an unused opcode, e.g. 0xF1 in this table:
   http://ref.x86asm.net/coder32.html
   2. Insert an instruction into lib/Target/X86/X86InstrInfo.td using this
   opcode.

In this case, I used 0xF1, and created the following instruction:

def CACHE_OPERAND_B64i : RIi64<0xF1, AddRegFrm, (outs GR64:$unused),
                (ins i64imm:$b), "cache_operand_b_i64\t$b",
                [(int_cache_operand_b_i64 i64imm:$b)]>,
                Requires<[In64BitMode]>;

However, when I compile, I'm getting errors of the form:

Error: Primary decode conflict: TEST64ri32 would overwrite
CACHE_OPERAND_B64i
ModRM   199
Opcode  247
Context IC_64BIT_REXW

When I look at the definition of TEST64ri32, I see:

let Predicates = [In64BitMode] in
def TEST64ri32 : BinOpRI_F<0xF6, "test", Xi64, X86testpat, MRM0r>;

It looks like TEST64ri32 is using opcode 0xF6 -- why is there a conflict
with 0xF1?

Even if I comment out TEST64ri32 (which I recognize is not a good idea), I
still get a similar error:

Error: Primary decode conflict: NOT64r would overwrite CACHE_OPERAND_B64i
ModRM   215
Opcode  247
Context IC_64BIT_REXW

Which corresponds to the definition:

def NOT64r : RI<0xF7, MRM2r, (outs GR64:$dst), (ins GR64:$src1),
                "not{q}\t$dst",
                [(set GR64:$dst, (not GR64:$src1))], IIC_UNARY_REG>;


Again, why does 0xF7 conflict with 0xF1?

Thanks,
Gus Smith

P.S. If this looks hacky, that's because it is; I'm not sure what the
correct way to add an instruction into x86 is, if there even is one.
Pointers along that line are appreciated.
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