[llvm-dev] Intended behavior of CGSCC pass manager.
Xinliang David Li via llvm-dev
llvm-dev at lists.llvm.org
Thu Jun 16 23:07:57 PDT 2016
On Thu, Jun 16, 2016 at 10:47 PM, Sean Silva <chisophugis at gmail.com> wrote:
>
>
> On Thu, Jun 16, 2016 at 9:53 PM, Xinliang David Li <davidxl at google.com>
> wrote:
>
>>
>>
>> On Thu, Jun 16, 2016 at 11:12 AM, Sanjoy Das <
>> sanjoy at playingwithpointers.com> wrote:
>>
>>> Hi Sean,
>>>
>>> On Thu, Jun 16, 2016 at 4:48 AM, Sean Silva via llvm-dev
>>> <llvm-dev at lists.llvm.org> wrote:
>>> > One question is what invariants we want to provide for the visitation.
>>> >
>>> > For example, should a CGSCC pass be able to assume that all "child"
>>> SCC's
>>> > (SCC's it can reach via direct calls emanating from the SCC being
>>> visited)
>>> > have already been visited? Currently I don't think it can, and IIRC
>>> from the
>>> > discussion at the social this is one thing that Chandler is hoping to
>>> fix.
>>> > The "ref edge" notion in LazyCallGraph ensures that we cannot create a
>>> call
>>> > edge (devirtualizing a ref edge) that will point at an SCC that has
>>> not yet
>>> > been visited.
>>> >
>>> > E.g. consider this graph:
>>> >
>>> > digraph G {
>>> > A -> B; B -> A; // SCC {A,B}
>>> > S -> T; T -> S; // SCC {S,T}
>>> > X -> Y; Y -> X; // SCC {X,Y}
>>> >
>>> > B -> X;
>>> > B -> S;
>>> > T -> Y [label="Ref edge that is devirtualized\nwhen visiting SCC
>>> > {S,T}",constraint=false,style=dashed]
>>> > }
>>> >
>>> > (can visualize conveniently at http://www.webgraphviz.com/ or I have
>>> put an
>>> > image at http://reviews.llvm.org/F2073104)
>>> >
>>> > If we do not consider the ref graph, then it is possible for SCC {S,T}
>>> to be
>>>
>>> I'm not sure why you wouldn't consider the ref graph? I think the
>>> general idea is to visit RefSCCs in bottom up order, and when visiting
>>> a RefSCC, visiting the SCC's inside the RefSCC in bottom up order.
>>>
>>> So in your example, given the edges you've shown, we will visit {X,Y}
>>> before visiting {S,T}.
>>>
>>> > A more complicated case is when SCC {S,T} and SCC {X,Y} both call into
>>> each
>>> > other via function pointers. So eventually after devirtualizing the
>>> calls in
>>> > both directions there will be a single SCC {S,T,X,Y}.
>>> >
>>> > digraph G {
>>> > A -> B; B -> A; // SCC {A,B}
>>> > S -> T; T -> S; // SCC {S,T}
>>> > X -> Y; Y -> X; // SCC {X,Y}
>>> >
>>> > B -> X;
>>> > B -> S;
>>> > T -> Y [label="Ref edge that is devirtualized\nwhen visiting SCC
>>> > {S,T}",constraint=false,style=dashed]
>>> > X -> S [label="Ref edge that is devirtualized\nwhen visiting SCC
>>> > {X,Y}",constraint=false,style=dashed]
>>> > }
>>> >
>>> > (rendering at: http://reviews.llvm.org/F2073479)
>>> >
>>> > Due to the cyclic dependence there is no SCC visitation order that can
>>> > directly provide the invariant above. Indeed, the problem of
>>> maintaining the
>>>
>>> I think the workflow in the above will (roughly) be:
>>>
>>> Visit the RefSCC {X,Y,S,T}
>>>
>>
>> Are we sure RefSCC has ref edges between {X, Y} and {S, T} in this case?
>> I may miss the code handling it.
>>
>
> The ref graph is conservative and so it would have the appropriate edges.
>
> https://github.com/llvm-project/llvm-project/blob/master/llvm/lib/Analysis/LazyCallGraph.cpp#L90
>
That is where the confusion is -- the findReferences's function body only
handles constant operands which may be function addresses. Did I miss
something obvious? Another point is that it may not be practical to model
edges to indirect targets. For virtual calls, without CHA, each virtual
callsite will end up referencing all potential address taken functions.
>
>
>
>>
>>
>>
>>> Visit the SCC {X,Y} // arbitrary
>>> Optimize({X,Y})
>>> // Now there's an edge to {S,T}, invalidate
>>> // the analyses cached for {X,Y} and visit {S,T}
>>>
>>
>> I am not sure if this makes sense. If dynamically, the call edge from
>> {X, Y} to {S, T} does exist, but not discovered by the analysis, then the
>> cached {X, Y} will still be invalid, but who is going to invalidate it?
>>
>
> I assume that if dynamically there was a call from {X,Y} to {S,T}, then
> the analysis would have observed an indirect call and would have behaved
> conservatively.
>
See above, I did not see how indirect call is handled. Also if the result
for {X, Y} is conservatively correct before the direct call edge is
discovered, why bother invalidating its analysis when the call edge is
exposed?
David
>
> -- Sean Silva
>
>
>>
>> David
>>
>>
>>
>>
>>
>>> Visit the SCC {S,T}
>>> Optimize({S,T})
>>> // Now {X,Y,S,T} collapses to form a single SCC
>>> Visit the SCC {S,T,X,Y}
>>> Optimize({S,T,X,Y})
>>>
>>> The difficult bit is to make the inner "// Now.*" bits work well.
>>>
>>> -- Sanjoy
>>>
>>
>>
>
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