[LLVMdev] Performance regression on ARM
Stephen Checkoway
s at pahtak.org
Sun Oct 19 18:10:26 PDT 2014
On Oct 18, 2014, at 5:25 PM, Joerg Sonnenberger <joerg at britannica.bec.de> wrote:
> On Sun, Oct 19, 2014 at 06:58:53AM +0700, C BergstrÃ¶m wrote:
>> On Sun, Oct 19, 2014 at 6:45 AM, Joerg Sonnenberger <joerg at britannica.bec.de
>>> wrote:
>>
>>> On Sun, Oct 19, 2014 at 06:31:24AM +0700, C BergstrÃ¶m wrote:
>>>> I apologize that I haven't been able to follow this thread entirely, but
>>> if
>>>> someone gives me a Fortran testcase I can check what Fortran+llvm would
>>> do
>>>> currently and maybe give more feedback.
>>>
>>> Short version: if you multiple or divide a complex number by a real
>>> number, is it valid to just do the trivial component wise computation?
>>> What about multiplying with / dividing by a pure imaginary number?
>>>
>>
>> I'll try to get a solid answer, but for clarity.. Fortran has types REAL
>> and CMPLX. I'm not sure if you mean INT or REAL when you say "real" number..
>
> I am using "real" in the mathematical sense, so cast/promotion from
> either INT or REAL would fit.
Mathematically, a*(b+ic) = ab +iac where a, b, and c are arbitrary real numbers. Division by nonzero a is identical to multiplication by 1/a. I have no idea what language specs say, however.
In general, multiplying complex numbers in rectangular form is pretty straight-forward:
(a+ib)(c+id) = ac - bd + i(ad+bc).
Division is a little more of a hassle:
(a+ib)/(c+id) = (a+ib)(c-id)/(c^2 + d^2)
= (ac + bd)/(c^2 + d^2) + i(bc - ad)/(c^2 + d^2).
(Polar form is more convenient for multiplication and division:
a*exp(is) * b*exp(it) = ab*exp(i(s+t))
and division by nonzero a*exp(is) is the same as multiplication by 1/a exp(-is). Addition and subtraction become annoying though.)
--
Stephen Checkoway
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