[LLVMdev] Structure Types and ABI sizes

[Jochen Wilhelmy]

> If you're saying that:
>
>    
>> %I = type { i32, i8 };
>>      
> has size 5, yes, you're missing the alignment.
>    
Ah, now I see. But I didn't say that

%I = type { i32, i8 };

has 5 bytes (because it has 8) but I thought that it has
5 bytes when being a member of %J, i.e.

%J = type { %I, i8 }

In this case %I also has 8 bytes right?
I was thinking too much in terms of C++ inheritance.

Then perhaps the tailpadding should be specified explicitly ;-)

%I = type { i32, i8 }; // 5 bytes
%I' = type { %I, tailpad}; // 8 bytes
%J = type { %I, i8 } // 6 bytes


-Jochen