[LLVMdev] c const

[Duncan Sands]

Hi Christopher,

> If A and B are function arguments then there is no "based on"  
> relationship between pointer expressions A+0 and B+0. This is because  
> changing one of the pointers, A for example, to point to a copy of  
> the object it points to would change the value of the pointer  
> expression A+0, but not the expression B+0.

I was assuming that *(A+0) and *(B+0) are pointer expressions.  Is
that not the case?

Thanks,

Duncan.