<div dir="ltr"><div class="gmail_extra"><div class="gmail_quote"><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div class=""><br>>> If we decided to support strict alignment mode efficiently, we would<br>

>> probably want to emit an "ld1 {v0.8b}" (i.e. always use the .8b or<br>
>> .16b version), since that's got the same semantics as ldr.<br>
><br>
> It is only true for little-endian, isn't it?<br>
<br>
</div>I don't believe so. I think "ld1 {v0.8b}" is equivalent to "ldr d0" on<br>
both endians (and the equivalent 16b statement).<br>
<div class=""><br></div></blockquote><div class="gmail_default" style="font-family:arial,helvetica,sans-serif;font-size:small"><br></div><div class="gmail_default" style="font-family:arial,helvetica,sans-serif;font-size:small">
Well, are you sure this is correct? I have been thinking they are different for big endian.</div><div class="gmail_default" style="font-family:arial,helvetica,sans-serif;font-size:small"><br></div><div class="gmail_default" style="font-family:arial,helvetica,sans-serif;font-size:small">
Thanks,</div><div class="gmail_default" style="font-family:arial,helvetica,sans-serif;font-size:small">-Jiangning</div></div>
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