Index: test/Transforms/InstCombine/and2.ll =================================================================== --- test/Transforms/InstCombine/and2.ll (revision 139870) +++ test/Transforms/InstCombine/and2.ll (working copy) @@ -35,3 +35,10 @@ ; CHECK: @test4 ; CHECK-NEXT: ret i1 false } + +; Make sure we don't go into an infinite loop with this test +define <4 x i32> @test5(<4 x i32> %A) { + %1 = xor <4 x i32> %A, + %2 = and <4 x i32> , %1 + ret <4 x i32> %2 +} Index: lib/Transforms/InstCombine/InstCombineAndOrXor.cpp =================================================================== --- lib/Transforms/InstCombine/InstCombineAndOrXor.cpp (revision 139870) +++ lib/Transforms/InstCombine/InstCombineAndOrXor.cpp (working copy) @@ -1174,30 +1174,31 @@ ((A == C && B == D) || (A == D && B == C))) return BinaryOperator::CreateXor(A, B); - if (Op0->hasOneUse() && - match(Op0, m_Xor(m_Value(A), m_Value(B)))) { - if (A == Op1) { // (A^B)&A -> A&(A^B) - I.swapOperands(); // Simplify below - std::swap(Op0, Op1); - } else if (B == Op1) { // (A^B)&B -> B&(B^A) - cast(Op0)->swapOperands(); - I.swapOperands(); // Simplify below - std::swap(Op0, Op1); + // A&(A^B) => A & ~B + { + Value *tmpOp0 = Op0; + Value *tmpOp1 = Op1; + if (Op0->hasOneUse() && + match(Op0, m_Xor(m_Value(A), m_Value(B)))) { + if (A == Op1 || B == Op1 ) { + tmpOp1 = Op0; + tmpOp0 = Op1; + // Simplify below + } } - } - if (Op1->hasOneUse() && - match(Op1, m_Xor(m_Value(A), m_Value(B)))) { - if (B == Op0) { // B&(A^B) -> B&(B^A) - cast(Op1)->swapOperands(); - std::swap(A, B); + if (tmpOp1->hasOneUse() && + match(tmpOp1, m_Xor(m_Value(A), m_Value(B)))) { + if (B == tmpOp0) { + std::swap(A, B); + } + // Notice that the patten (A&(~B)) is actually (A&(-1^B)), so if + // A is originally -1 (or a vector of -1 and undefs), then we enter + // an endless loop. By checking that A is non-constant we ensure that + // we will never get to the loop. + if (A == tmpOp0 && !isa(A)) // A&(A^B) -> A & ~B + return BinaryOperator::CreateAnd(A, Builder->CreateNot(B, "tmp")); } - // Notice that the patten (A&(~B)) is actually (A&(-1^B)), so if - // A is originally -1 (or a vector of -1 and undefs), then we enter - // an endless loop. By checking that A is non-constant we ensure that - // we will never get to the loop. - if (A == Op0 && !isa(A)) // A&(A^B) -> A & ~B - return BinaryOperator::CreateAnd(A, Builder->CreateNot(B, "tmp")); } // (A&((~A)|B)) -> A&B