[llvm] r300376 - [InstCombine] MakeAnd/Or/Xor handling to reuse previous APInt computations
Craig Topper via llvm-commits
llvm-commits at lists.llvm.org
Fri Apr 14 15:34:14 PDT 2017
Author: ctopper
Date: Fri Apr 14 17:34:14 2017
New Revision: 300376
URL: http://llvm.org/viewvc/llvm-project?rev=300376&view=rev
Log:
[InstCombine] MakeAnd/Or/Xor handling to reuse previous APInt computations
When checking if we should return a constant, we create some temporary APInts to see if we know all bits. But the exact computations we do are needed in several other locations in the same code.
This patch moves them to named temporaries so we can reuse them.
Ideally we'd write directly to KnownZero/One, but we currently seem to only write those variables after all the simplifications checks and I didn't want to change that with this patch.
Differential Revision: https://reviews.llvm.org/D32094
Modified:
llvm/trunk/lib/Transforms/InstCombine/InstCombineSimplifyDemanded.cpp
Modified: llvm/trunk/lib/Transforms/InstCombine/InstCombineSimplifyDemanded.cpp
URL: http://llvm.org/viewvc/llvm-project/llvm/trunk/lib/Transforms/InstCombine/InstCombineSimplifyDemanded.cpp?rev=300376&r1=300375&r2=300376&view=diff
==============================================================================
--- llvm/trunk/lib/Transforms/InstCombine/InstCombineSimplifyDemanded.cpp (original)
+++ llvm/trunk/lib/Transforms/InstCombine/InstCombineSimplifyDemanded.cpp Fri Apr 14 17:34:14 2017
@@ -170,7 +170,7 @@ Value *InstCombiner::SimplifyDemandedUse
default:
computeKnownBits(I, KnownZero, KnownOne, Depth, CxtI);
break;
- case Instruction::And:
+ case Instruction::And: {
// If either the LHS or the RHS are Zero, the result is zero.
if (SimplifyDemandedBits(I, 1, DemandedMask, RHSKnownZero, RHSKnownOne,
Depth + 1) ||
@@ -180,11 +180,15 @@ Value *InstCombiner::SimplifyDemandedUse
assert(!(RHSKnownZero & RHSKnownOne) && "Bits known to be one AND zero?");
assert(!(LHSKnownZero & LHSKnownOne) && "Bits known to be one AND zero?");
+ // Output known-0 are known to be clear if zero in either the LHS | RHS.
+ APInt IKnownZero = RHSKnownZero | LHSKnownZero;
+ // Output known-1 bits are only known if set in both the LHS & RHS.
+ APInt IKnownOne = RHSKnownOne & LHSKnownOne;
+
// If the client is only demanding bits that we know, return the known
// constant.
- if ((DemandedMask & ((RHSKnownZero | LHSKnownZero)|
- (RHSKnownOne & LHSKnownOne))) == DemandedMask)
- return Constant::getIntegerValue(VTy, RHSKnownOne & LHSKnownOne);
+ if ((DemandedMask & (IKnownZero|IKnownOne)) == DemandedMask)
+ return Constant::getIntegerValue(VTy, IKnownOne);
// If all of the demanded bits are known 1 on one side, return the other.
// These bits cannot contribute to the result of the 'and'.
@@ -199,12 +203,11 @@ Value *InstCombiner::SimplifyDemandedUse
if (ShrinkDemandedConstant(I, 1, DemandedMask & ~LHSKnownZero))
return I;
- // Output known-1 bits are only known if set in both the LHS & RHS.
- KnownOne = RHSKnownOne & LHSKnownOne;
- // Output known-0 are known to be clear if zero in either the LHS | RHS.
- KnownZero = RHSKnownZero | LHSKnownZero;
+ KnownZero = std::move(IKnownZero);
+ KnownOne = std::move(IKnownOne);
break;
- case Instruction::Or:
+ }
+ case Instruction::Or: {
// If either the LHS or the RHS are One, the result is One.
if (SimplifyDemandedBits(I, 1, DemandedMask, RHSKnownZero, RHSKnownOne,
Depth + 1) ||
@@ -214,11 +217,15 @@ Value *InstCombiner::SimplifyDemandedUse
assert(!(RHSKnownZero & RHSKnownOne) && "Bits known to be one AND zero?");
assert(!(LHSKnownZero & LHSKnownOne) && "Bits known to be one AND zero?");
+ // Output known-0 bits are only known if clear in both the LHS & RHS.
+ APInt IKnownZero = RHSKnownZero & LHSKnownZero;
+ // Output known-1 are known to be set if set in either the LHS | RHS.
+ APInt IKnownOne = RHSKnownOne | LHSKnownOne;
+
// If the client is only demanding bits that we know, return the known
// constant.
- if ((DemandedMask & ((RHSKnownZero & LHSKnownZero)|
- (RHSKnownOne | LHSKnownOne))) == DemandedMask)
- return Constant::getIntegerValue(VTy, RHSKnownOne | LHSKnownOne);
+ if ((DemandedMask & (IKnownZero|IKnownOne)) == DemandedMask)
+ return Constant::getIntegerValue(VTy, IKnownOne);
// If all of the demanded bits are known zero on one side, return the other.
// These bits cannot contribute to the result of the 'or'.
@@ -242,11 +249,10 @@ Value *InstCombiner::SimplifyDemandedUse
if (ShrinkDemandedConstant(I, 1, DemandedMask))
return I;
- // Output known-0 bits are only known if clear in both the LHS & RHS.
- KnownZero = RHSKnownZero & LHSKnownZero;
- // Output known-1 are known to be set if set in either the LHS | RHS.
- KnownOne = RHSKnownOne | LHSKnownOne;
+ KnownZero = std::move(IKnownZero);
+ KnownOne = std::move(IKnownOne);
break;
+ }
case Instruction::Xor: {
if (SimplifyDemandedBits(I, 1, DemandedMask, RHSKnownZero, RHSKnownOne,
Depth + 1) ||
@@ -329,9 +335,9 @@ Value *InstCombiner::SimplifyDemandedUse
}
// Output known-0 bits are known if clear or set in both the LHS & RHS.
- KnownZero= (RHSKnownZero & LHSKnownZero) | (RHSKnownOne & LHSKnownOne);
+ KnownZero = std::move(IKnownZero);
// Output known-1 are known to be set if set in only one of the LHS, RHS.
- KnownOne = (RHSKnownZero & LHSKnownOne) | (RHSKnownOne & LHSKnownZero);
+ KnownOne = std::move(IKnownOne);
break;
}
case Instruction::Select:
@@ -763,18 +769,22 @@ Value *InstCombiner::SimplifyMultipleUse
// do simplifications that apply to *just* the one user if we know that
// this instruction has a simpler value in that context.
switch (I->getOpcode()) {
- case Instruction::And:
+ case Instruction::And: {
// If either the LHS or the RHS are Zero, the result is zero.
computeKnownBits(I->getOperand(1), RHSKnownZero, RHSKnownOne, Depth + 1,
CxtI);
computeKnownBits(I->getOperand(0), LHSKnownZero, LHSKnownOne, Depth + 1,
CxtI);
+ // Output known-0 are known to be clear if zero in either the LHS | RHS.
+ APInt IKnownZero = RHSKnownZero | LHSKnownZero;
+ // Output known-1 bits are only known if set in both the LHS & RHS.
+ APInt IKnownOne = RHSKnownOne & LHSKnownOne;
+
// If the client is only demanding bits that we know, return the known
// constant.
- if ((DemandedMask & ((RHSKnownZero | LHSKnownZero)|
- (RHSKnownOne & LHSKnownOne))) == DemandedMask)
- return Constant::getIntegerValue(ITy, RHSKnownOne & LHSKnownOne);
+ if ((DemandedMask & (IKnownZero|IKnownOne)) == DemandedMask)
+ return Constant::getIntegerValue(ITy, IKnownOne);
// If all of the demanded bits are known 1 on one side, return the other.
// These bits cannot contribute to the result of the 'and' in this
@@ -786,13 +796,11 @@ Value *InstCombiner::SimplifyMultipleUse
(DemandedMask & ~RHSKnownZero))
return I->getOperand(1);
- // Output known-1 bits are only known if set in both the LHS & RHS.
- KnownOne = RHSKnownOne & LHSKnownOne;
- // Output known-0 are known to be clear if zero in either the LHS | RHS.
- KnownZero = RHSKnownZero | LHSKnownZero;
+ KnownZero = std::move(IKnownZero);
+ KnownOne = std::move(IKnownOne);
break;
-
- case Instruction::Or:
+ }
+ case Instruction::Or: {
// We can simplify (X|Y) -> X or Y in the user's context if we know that
// only bits from X or Y are demanded.
@@ -802,11 +810,15 @@ Value *InstCombiner::SimplifyMultipleUse
computeKnownBits(I->getOperand(0), LHSKnownZero, LHSKnownOne, Depth + 1,
CxtI);
+ // Output known-0 bits are only known if clear in both the LHS & RHS.
+ APInt IKnownZero = RHSKnownZero & LHSKnownZero;
+ // Output known-1 are known to be set if set in either the LHS | RHS.
+ APInt IKnownOne = RHSKnownOne | LHSKnownOne;
+
// If the client is only demanding bits that we know, return the known
// constant.
- if ((DemandedMask & ((RHSKnownZero & LHSKnownZero)|
- (RHSKnownOne | LHSKnownOne))) == DemandedMask)
- return Constant::getIntegerValue(ITy, RHSKnownOne | LHSKnownOne);
+ if ((DemandedMask & (IKnownZero|IKnownOne)) == DemandedMask)
+ return Constant::getIntegerValue(ITy, IKnownOne);
// If all of the demanded bits are known zero on one side, return the
// other. These bits cannot contribute to the result of the 'or' in this
@@ -827,12 +839,10 @@ Value *InstCombiner::SimplifyMultipleUse
(DemandedMask & (~LHSKnownZero)))
return I->getOperand(1);
- // Output known-0 bits are only known if clear in both the LHS & RHS.
- KnownZero = RHSKnownZero & LHSKnownZero;
- // Output known-1 are known to be set if set in either the LHS | RHS.
- KnownOne = RHSKnownOne | LHSKnownOne;
+ KnownZero = std::move(IKnownZero);
+ KnownOne = std::move(IKnownOne);
break;
-
+ }
case Instruction::Xor: {
// We can simplify (X^Y) -> X or Y in the user's context if we know that
// only bits from X or Y are demanded.
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