[compiler-rt] r193098 - Use internal_memset to initialize this variable.

Richard Smith richard at metafoo.co.uk
Mon Oct 21 11:23:45 PDT 2013


This is pretty scary. Is there a flag we can use to avoid memset being
implicitly called here? -fno-builtin or similar?


On Mon, Oct 21, 2013 at 11:11 AM, Peter Collingbourne <peter at pcc.me.uk>wrote:

> Author: pcc
> Date: Mon Oct 21 13:11:57 2013
> New Revision: 193098
>
> URL: http://llvm.org/viewvc/llvm-project?rev=193098&view=rev
> Log:
> Use internal_memset to initialize this variable.
>
> Otherwise, the compiler may use memset in non-optimized builds, which is
> forbidden in the nolibc part of the runtime.
>
> Modified:
>     compiler-rt/trunk/lib/sanitizer_common/sanitizer_linux.cc
>
> Modified: compiler-rt/trunk/lib/sanitizer_common/sanitizer_linux.cc
> URL:
> http://llvm.org/viewvc/llvm-project/compiler-rt/trunk/lib/sanitizer_common/sanitizer_linux.cc?rev=193098&r1=193097&r2=193098&view=diff
>
> ==============================================================================
> --- compiler-rt/trunk/lib/sanitizer_common/sanitizer_linux.cc (original)
> +++ compiler-rt/trunk/lib/sanitizer_common/sanitizer_linux.cc Mon Oct 21
> 13:11:57 2013
> @@ -218,7 +218,8 @@ uptr GetTid() {
>  }
>
>  u64 NanoTime() {
> -  kernel_timeval tv = {};
> +  kernel_timeval tv;
> +  internal_memset(&tv, 0, sizeof(tv));
>    internal_syscall(__NR_gettimeofday, &tv, 0);
>    return (u64)tv.tv_sec * 1000*1000*1000 + tv.tv_usec * 1000;
>  }
>
>
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