<html>
    <head>
      <base href="https://llvm.org/bugs/" />
    </head>
    <body><table border="1" cellspacing="0" cellpadding="8">
        <tr>
          <th>Bug ID</th>
          <td><a class="bz_bug_link 
          bz_status_NEW "
   title="NEW --- - MIPS back end performs inefficient subtraction of immediates"
   href="https://llvm.org/bugs/show_bug.cgi?id=26291">26291</a>
          </td>
        </tr>

        <tr>
          <th>Summary</th>
          <td>MIPS back end performs inefficient subtraction of immediates
          </td>
        </tr>

        <tr>
          <th>Product</th>
          <td>libraries
          </td>
        </tr>

        <tr>
          <th>Version</th>
          <td>trunk
          </td>
        </tr>

        <tr>
          <th>Hardware</th>
          <td>PC
          </td>
        </tr>

        <tr>
          <th>OS</th>
          <td>All
          </td>
        </tr>

        <tr>
          <th>Status</th>
          <td>NEW
          </td>
        </tr>

        <tr>
          <th>Severity</th>
          <td>normal
          </td>
        </tr>

        <tr>
          <th>Priority</th>
          <td>P
          </td>
        </tr>

        <tr>
          <th>Component</th>
          <td>Backend: MIPS
          </td>
        </tr>

        <tr>
          <th>Assignee</th>
          <td>unassignedbugs@nondot.org
          </td>
        </tr>

        <tr>
          <th>Reporter</th>
          <td>csdavec@swan.ac.uk
          </td>
        </tr>

        <tr>
          <th>CC</th>
          <td>llvm-bugs@lists.llvm.org
          </td>
        </tr>

        <tr>
          <th>Classification</th>
          <td>Unclassified
          </td>
        </tr></table>
      <p>
        <div>
        <pre>Simple C test case:

int foo(char*,char*, char*);

int main(void)
{
    char z[1048576];
    foo(z,z,z);
}

The key part of the IR:

%z = alloca [1048576 x i8], align 1

This produces the following code for the stack pointer modification:

    daddiu    $5, $zero, 1
    dsll    $5, $5, 44
    daddiu    $5, $5, -1
    dsll    $5, $5, 20
    daddiu    $5, $5, -48
    daddu    $sp, $sp, $5

This would be much simpler as

lui   $5, 16
dsubu $sp, $sp, $5

Even without rewriting the add as a subtraction, the constant could be
materialised as:

lui   $5, 16
dsubu $5, $zero, $5</pre>
        </div>
      </p>
      <hr>
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