[lldb-dev] Disassembling with no function bounds
zturner at google.com
Wed Jan 21 14:24:14 PST 2015
It looks like I just overlooked -s.
So armed with that knowledge, is there any objection to adding, say, -x,
which is more or less "continue disassembling at the last address"?
On Wed Jan 21 2015 at 2:19:38 PM <jingham at apple.com> wrote:
> Yeah, the help says:
> -a <address-expression> ( --address <address-expression> )
> Disassemble function containing this address.
> so it is doing what is expected. You don't need to specify -c or -e, it
> will dump some default number of instructions. Having it do something
> reasonable when there is no function containing that address is not totally
> unreasonable, except then -a and -s overlap in function, which is a little
> > On Jan 21, 2015, at 2:10 PM, Ed Maste <emaste at freebsd.org> wrote:
> > On 21 January 2015 at 16:57, Zachary Turner <zturner at google.com> wrote:
> >> Is there any way to work around this restriction? It seems like it
> >> shouldn't matter what the bounds of the function are, or if there's
> even a
> >> function at this address at all. As long as there's code.
> > You should be able to use a combination of -s start address / -e end
> > address / -c instruction count.
> > Perhaps we could disassemble a small number of instructions starting
> > from the provided address if -a is given an address outside of a
> > function.
> > _______________________________________________
> > lldb-dev mailing list
> > lldb-dev at cs.uiuc.edu
> > http://lists.cs.uiuc.edu/mailman/listinfo/lldb-dev
-------------- next part --------------
An HTML attachment was scrubbed...
More information about the lldb-dev