[lldb-dev] executing a c++ function from lldb python script

Niels Bogaards niels at elephantcandy.com
Tue Jan 7 05:22:59 PST 2014


I made a script for lldb last year that allowed me to plot a custom object as a curve from Xcode’s lldb prompt. Worked very well for a year, but no more. Has anything changed in the EvaluateExpression syntax? Are there linker options I need to activate in my target c++ program?

Thanks for any help,


Here's the script, it outputs: 

 - DEBUG - res is No value
 - DEBUG - fname is No value
 - DEBUG - error is error: <NULL>

import lldb
import commands
import optparse
import shlex
import logging

def plot(debugger, command, result, dict):
	logging.basicConfig(level=logging.DEBUG, format='%(asctime)s - %(levelname)s - %(message)s')
	command_args = shlex.split(command)
	usage = "usage: %prog objectName "
	parser = optparse.OptionParser(description=description, prog='plot',usage=usage)
		(options, args) = parser.parse_args(command_args)
		print '"plot" exception'
	la = len(args)
	print 'len args = %d' % la
	if len(args) == 1:
		ecom = “MyNamespace::MyClass::MyStaticPlotFunction(%s)" % args[0]
		res = lldb.frame.EvaluateExpression(ecom, 1)
		fname = lldb.frame.EvaluateExpression("MyNamespace::MyClass::GetStaticPlotFileName()")
		error = lldb.SBError()
		logging.debug("res is %s", res);
		logging.debug("fname is %s", fname);
		logging.debug("error is %s", error);

if __name__ == '__main__':
    # This script is being run from the command line, create a debugger in case we are
    # going to use any debugger functions in our function.
    lldb.debugger = lldb.SBDebugger.Create()
    plot (sys.argv)

def __lldb_init_module (debugger, dict):
    # This initializer is being run from LLDB in the embedded command interpreter
    # Add any commands contained in this module to LLDB
    debugger.HandleCommand('command script add -f plot.plot plot')
    print '"plot" command installed, type "plot --help" for detailed help'

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