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<p><font size="+1">Hi Michael,</font></p>
<p><font size="+1">I looked into two methods of traversing the AST.
One is using libClang and its CXCursor, and the other using
libTooling. From the document, it seems that libClang is good
enough to traverse the AST, but when I started doing it, it
isn't easy to get the content of a node. For example, there is
no interface that gives the content of a binary operator
directly. For this reason, I prefer to use the libTooling
library. Do you have any suggestions about which way to go?</font><br>
</p>
<pre class="moz-signature" cols="72">Love,
Lou
</pre>
<div class="moz-cite-prefix">On 10/24/18 12:41 AM, Michael Kruse
wrote:<br>
</div>
<blockquote type="cite"
cite="mid:CADPO-WABy7vFG=GBpPxmbddZKV5zmEtRZkvDDuYi5UG6BGETHA@mail.gmail.com">
<pre class="moz-quote-pre" wrap="">The Rewriter is useful if you want to make small changes and keep the
remaining untouched (formatting, whitespace, ...). If you target a
different language, you probably do not want/need to preserve
anything, so a recursive traversal is the right thing to do. It also
saves you from having to handle #include and forward declarations,
which probably do not have the same semantics in your target language.
"Probably", because there are two language rewriters in clang:
RewriteObjC/RewriteModernObjC (Objective C -> C) and HTMLRewriter
(ObjC/C/C++ -> HTML)
Michael
Am Di., 23. Okt. 2018 um 03:59 Uhr schrieb Lou Wynn via cfe-dev
<a class="moz-txt-link-rfc2396E" href="mailto:cfe-dev@lists.llvm.org"><cfe-dev@lists.llvm.org></a>:
</pre>
<blockquote type="cite">
<pre class="moz-quote-pre" wrap="">
Hi,
I'm writing a source to source translation tool which accepts Clang AST and outputs source code of another language. My original plan was to traverse the AST of a translation unit and outputs corresponding source code of the target language, but I've noticed that there is a Rewriter and I'm not sure if the Rewriter works for my purpose.
I've just started using Clang AST, and I appreciate any suggestion and example.
--
Love,
Lou
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</pre>
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