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<p class="MsoNormal"><span style="font-size:11.0pt">Hi,<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">I am writing a replacement to move arguments from one function to another.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">For instance,<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">foo(arg1) -> foo().bar(arg1)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">foo(*arg2) -> foo().bar(*arg2)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">foo(…) -> foo().bar(…)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">where arg1, arg2, … are resolved to the same type.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">I am able to handle the first case doing something like this:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">matcher = callExpr(callee(functionDecl(hasName(“foo”)))).bind(call)<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">replacements.emplace(sourceManager,
<br>
call->getArg(0)->getExprLoc(), <br>
Lexer::getLocForEndOfToken(call->getArg(0)->getExprLoc(),
<br>
0,
<o:p></o:p></span></p>
<p class="MsoNormal" style="margin-left:238.5pt"><span style="font-size:11.0pt">sourceManager,
<br>
context.getLangOpts())),<o:p></o:p></span></p>
<p class="MsoNormal" style="margin-left:1.0in"><span style="font-size:11.0pt"> “”);<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">Which is able to change “foo(arg1)” to foo().bar(arg1). However, for cases with UnaryOperators inbetween, the outcome is:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">“foo(*arg2)” -> “foo(arg2).bar(*arg2). It only considers the unary operator and does not remove the “arg2” portion of the argument.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">I cannot figure out a clean way to do this. What is the suggested way to get that argument regardless of what operators that could be in front of it?<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">Note: I am trying to remove that argument completely.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">Thanks,<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt">David Lai<br>
<br>
<o:p></o:p></span></p>
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