[cfe-dev] convert conditional expression to string
Kihong Heo via cfe-dev
cfe-dev at lists.llvm.org
Wed Dec 5 20:39:22 PST 2018
It seems Expr::getSourceRange() returns the range of the first token.
Then, in this particular case, what is the most common way to get the last token of the expression? How can I get “x < 10”?
> 2018. 12. 2. 오후 1:30, Richard Smith <richard at metafoo.co.uk> 작성:
> On Sat, 1 Dec 2018, 22:16 Alexey Sidorin via cfe-dev <cfe-dev at lists.llvm.org <mailto:cfe-dev at lists.llvm.org> wrote:
> Hi Kihong,
> The problem in your particular case is that the begin location of
> integer literal is reported as the end location (should we fix it in AST)?
> No, that's just how clang represents source ranges: source ranges are inclusive and source locations are the locations of tokens. So the start and end location of an integer literal should be the same, and the user needs to find the end of the last token themselves.
> As a workaround, you can try to use Lexer::getLocForEndOfToken() to get
> the token end location for the location reported by getLocEnd().
> 02.12.2018 8:36, Kihong Heo via cfe-dev пишет:
> > Hi all,
> > How can I get string representations of conditional expressions of IfStmt?
> > The problem is as follows:
> > For example;
> > =============
> > /* source code */
> > if( x < 10) …
> > =============
> > “IS->getCond()->getSourceRange()” represents only “x <“. It seems quite strange.
> > Thanks,
> > Kihong
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