[cfe-dev] why is such a code allowed?

[Matthew Plant]

From a C perspective this makes perfect sense as there is no "bool" types, if statements branch based on a value not being zero rather than not being logically true. 

From a C++ perspective, where the typing is more strict, I have copied this bit from the Microsoft C++ site which was the first thing I could find on the subject and I assume is standard conforming:

The bool type participates in integral promotions. An r-value of type bool can be converted to an r-value of type int, with false becoming zero and true becoming one. As a distinct type, bool participates in overload resolution.


> On Feb 6, 2015, at 10:19 AM, Guy Maurel <guy.maurel at kde.org> wrote:
> 
> Hello!
> 
> Let say: 
>    int a = 5;
>    int b = 7;
>    int i = 20;
>    if ((a  == b) + i) {
>        a = 15;
>    }
> My question is:
> The expression (a == b) gives a bool result.
> Why is it allowed to add a "bool" and an "int".
> 
> Thanks
> -- 
> Guy Maurel
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