[PATCH] Teach libc++ to use __builtin_operator_new/__builtin_operator_delete when available

Marshall Clow mclow.lists at gmail.com
Wed Jun 4 08:02:35 PDT 2014

On Jun 3, 2014, at 3:14 PM, Richard Smith <richard at metafoo.co.uk> wrote:

> Hi!
> This patch causes libc++ to use Clang's new __builtin_operator_new and __builtin_operator_delete builtins when possible. These builtins allow optimizations that the standard builtins do not: in particular, if we can remove all uses of an allocation, this permits removing the allocation itself too.
> In particular, this allows code using std::vector and its kin to be optimized away to nothing. Previously it would get optimized to the point where only the allocation and deallocation remained.
> This change has been applied to most calls to ::operator new and ::operator delete in libc++; I believe such optimizations are permitted by the specification of all affected library components.
> The exceptions are:
>  * get_temporary_buffer wants to call nothrow new, and we don't support that with the builtins (that would require teaching Clang about std::nothrow_t)
>  * __refstring is not affected; this doesn't seem particularly worthwhile since the only purpose for it is ABI interoperability with GCC
> One other caveat: the patch adds an include of <new> to <valarray>. <new> is extremely light, so I doubt this is a problem, but I thought it was worth calling out.

The code here looks quite straightforward.
I don’t see any problems - but I do have questions.

How does __builtin_operator_new/__builtin_operator_delete work if a user provides their own
global operator new/delete ?

For example, given code like this:

$ cat junk1.cpp

int main () {
	// something that eventually calls __builtin_operator_new

$ cat junk2.cpp
#include <new>

char buffer[10240];
size_t offset = 0;

void * operator new(size_t sz) throw(std::bad_alloc) {
	void *p = &buffer[offset];
	offset += sz;
	return p;
void operator delete(void *) {}

does the user’s operator new get called?

— Marshall

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